m^2-23m-130=0

Solution for m^2-23m-130=0 equation:

m^2-23m-130=0

a = 1; b = -23; c = -130;
Δ = b2-4ac
Δ = -232-4·1·(-130)
Δ = 1049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-\sqrt{1049}}{2*1}=\frac{23-\sqrt{1049}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+\sqrt{1049}}{2*1}=\frac{23+\sqrt{1049}}{2}
$